{VERSION 6 0 "IBM INTEL NT" "6.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 0 }{PSTYLE "Norma l" -1 0 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 1" -1 3 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }1 1 0 0 8 4 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 2" -1 4 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 14 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }1 1 0 0 8 2 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 " Times New Roman CE" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Output" -1 12 1 {CSTYLE "" -1 -1 "Times Ne w Roman CE" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Plot" -1 13 1 {CSTYLE "" -1 -1 "Times New Roman CE " 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 } {PSTYLE "Heading 1" -1 256 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }3 1 0 0 8 4 1 0 1 0 2 2 0 1 }{PSTYLE " Normal" -1 257 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Normal" -1 258 1 {CSTYLE "" -1 -1 "Times New Roman CE" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT 256 9 "FCH - B10" }}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 44 "V\375po\350et koncentrace oxidu uhli\350i t\351ho ve vod\354" }}{PARA 0 "" 0 "" {TEXT -1 496 "V jednolitrov\351 \+ sifonov\351 l\341hvi je 0,75 dm^3 vody(1) o teplot\354 20 \260C, parn \355 prostor m\341 objem 0,25 dm^3. Vypo\350\355tejte hmotnost CO2 (v \+ g), kter\341 se rozpust\355 ve vod\354 p\370i p\370\355prav\354 sodovk y. P\370edpokl\341dejte, \236e z bombi\350ky p\370ejde do sifonov\351 \+ l\341hve 5 g CO2(2). Ur\350ete rovn\354\236 tlak v sifonov\351 l\341hv i. Henryho konstanta pro rozpustnost CO2 ve vod\354 p\370i 20 \260C j e 144 MPa. K v\375po\350tu p-V-T chov\341n\355 oxidu uhli\350it\351ho \+ v parn\355 f\341zi pou\236ijte stavovou rovnici ide\341ln\355ho plynu. [m2 = 3.69 g, pCO2 = 0,29 MPa, p = 0,39 MPa]" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 " Data" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 39 "Vl:=0.75e-3; Vg:=0.2 5e-3; T:=20+273.15;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#VlG$\"#v!\"& " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#VgG$\"#D!\"&" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%\"TG$\"&:$H!\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "m2:=5e-3; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#m2G$ \"\"&!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "H:=144e6;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"HG$\"$W\"\"\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 54 "M1:=0.018; M2:=0.044; R:=8.314; rhol:=1e3; \+ p0:=101325;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#M1G$\"#=!\"$" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#M2G$\"#W!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"RG$\"%9$)!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% %rholG$\"\"\"\"\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#p0G\"'D85" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 " " {TEXT -1 6 "\330e\232en\355" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "n2:=m2/M2; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#n2G$\"+OOOO6!# 5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "n1:=Vl*rhol/M1;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#n1G$\"+nmmmT!\")" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "r1:=n2=n2g+n2l;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r1G/$\"+OOOO6!#5,&%$n2gG\"\"\"%$n2lGF+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "r2:=p2=n2g*R*T/Vg;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r2G/%#p2G,$*&$\"++k**[(*!\"$\"\"\"%$n2gGF,F," } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "r3:=p2=H*n2l/(n1+n2l);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r3G/%#p2G,$*($\"$W\"\"\"'\"\"\"%$n2 lGF,,&$\"+nmmmT!\")F,F-F,!\"\"F," }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "fsolve(\{r1,r2,r3\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<%/%$n2gG$\"+wSmpH!#6/%$n2lG$\"+%GsRR)F(/%#p2G$\"+RW7&*G!\"%" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "assign(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "P:=p2+p0;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"PG$\"+RWP3R!\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "m2l:=n2l*M2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$m2 lG$\"+0yM$p$!#7" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "c2l:=m2l /Vl;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$c2lG$\"+SPYC\\!\"*" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "c2g:=n2g*M2/Vg;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$c2gG$\"+s(3mA&!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 32 "V\375 po\350et rozpu\232t\354n\355 dus\355ku v krvi" }}{PARA 258 "" 0 "" {TEXT -1 553 " Pot\341p\354\350sk\341 nemoc je vyvol\341na t\355m, \+ \236e se bublinky dus\355ku rozpu\232t\354n\351ho v krvi uvol\362uj \355 v d\371sledku sn\355\236en\355 tlaku p\370i rychl\351m n\341vratu potap\354\350e k hladin\354 a br\341n\355 krevn\355mu ob\354hu. Za p \370edpokladu, \236e rozpustnost dus\355ku v krvi je stejn\341 jako ve vod\354, vypo\350t\354te objem dus\355ku uvoln\354n\351ho z krve (ply nn\375 stav; t = 37\260C, p = 100 kPa) p\370i rychl\351m n\341vratu p otap\354\350e ke hladin\354 z hloubky 60 m. P\370edpokl\341dejte, \236 e lidsk\351 t\354lo obsahuje 6 dm^3 krve, hustota mo\370sk\351 vody je 1,04 g/cm^3 a KH = 10000 MPa. (K desorpci kysl\355ku nedoch\341z \355, proto\236e ten je v\341z\341n na hemoglobin.)" }}{PARA 0 "" 0 " " {TEXT -1 17 "[VN2 = 415 cm^3] " }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 "Data" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "Vk:=0.006; T:=37+273.15; p:= 100e3;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#VkG$\"\"'!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"TG$\"&:5$!\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"pG$\"$+\"\"\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 32 "h:=60; rho:=1.04e3; KH:=10000e6;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"hG\"#g" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$rhoG$ \"$/\"\"\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#KHG$\"&++\"\"\"'" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "g:=9.81; R:=8.314;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG$\"$\")*!\"#" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%\"RG$\"%9$)!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "Mv:=0.018;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#MvG$ \"#=!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 "\330e\232en\355" }}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 12 "Dp:=h*rho*g;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%# DpG$\"(S97'!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "nV:=Vk* 1000./Mv;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#nVG$\"+LLLLL!\"(" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "r:=Dp=KH*n/(n+nV);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"rG/$\"(S97'!\"\",$*($\"&++\"\"\"'\"\"\"% \"nGF.,&F/F.$\"+LLLLL!\"(F.F(F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "solve(\{r\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<#/%\"nG$\"+9 \\gS?!#6" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "assign(%);" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "V:=n*R*T/p;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"VG$\"+1v(=E&!#8" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 37 "Rovnov\341 ha kapalina-kapalina - titrace" }}{PARA 0 "" 0 "" {TEXT -1 387 "Koexis tuj\355c\355 kapaln\351 f\341ze v syst\351mu voda(1) + 1-butanol(2) ma j\355 p\370i 25 \260C slo\236en\355 vyj\341d\370en\351 mol\341rn\355m \+ zlomkem vody x1(I)=0,511 a x1(II)=0,981. Zjist\354te, zda v syst\351mu vzniknou dv\354 kapaln\351 f\341ze, jestli\236e sm\355ch\341me 100 g \+ vody a 100 g 1-butanolu. Pokud ano, ur\350ete jejich l\341tkov\351 mno \236stv\355 a hmotnost vody (v g), kterou mus\355me p\370idat, aby vym izela butanolov\341 f\341ze. (M_butanol = 74,08 g /mol). " }}{PARA 0 " " 0 "" {TEXT -1 97 "[V syst\351mu se vytvo\370\355 2 f\341ze. n(vod.f. ) = 4,31 mol, n(but.f.) = 2,59 mol, m = 1155 g vody.] " }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 " " {TEXT -1 4 "Data" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "m1:=10 0.; m2:=100.;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#m1G$\"$+\"\"\"!" } }{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#m2G$\"$+\"\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "x1I:=0.511; x1II:=0.981;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$x1IG$\"$6&!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%x1IIG$\"$\")*!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 " M1:=18.; M2:=74.08;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#M1G$\"#=\"\" !" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#M2G$\"%3u!\"#" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 "\330e\232en\355" }}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 21 "n1:=m1/M1; n2:=m2/M2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#n1G$\"+cbbbb!\"*" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#n2G$\" +4?*)\\8!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "x1glob:=n1/ (n1+n2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%'x1globG$\"+1\"y^/)!#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "x2I:=1-x1I; x2II:=1-x1II; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$x2IG$\"$*[!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%x2IIG$\"#>!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "r1:=n1+n2=nI+nII;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6# >%#r1G/$\"+lvW0p!\"*,&%#nIG\"\"\"%$nIIGF+" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 23 "r2:=n1=nI*x1I+nII*x1II;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r2G/$\"+cbbbb!\"*,&*&$\"$6&!\"$\"\"\"%#nIGF.F.*&$\"$ \")*F-F.%$nIIGF.F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "r3:=n 2=nI*x2I+nII*x2II;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r3G/$\"+4?*) \\8!\"*,&*&$\"$*[!\"$\"\"\"%#nIGF.F.*&$\"#>F-F.%$nIIGF.F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "fsolve(\{r1,r2\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<$/%$nIIG$\"+(H$\\7V!\"*/%#nIG$\"+oU&Hf#F(" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 "r4:=x1II=(n1+Dn1)/(n1+Dn1+n2 );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r4G/$\"$\")*!\"$*&,&$\"+cbbbb !\"*\"\"\"%$Dn1GF.F.,&$\"+lvW0pF-F.F/F.!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "solve(\{r4\});" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#<#/%$Dn1G$\"+G+:9k!\")" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "assign(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "Dm1:=M1*Dn1; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$Dm1G$\"+0qaa6!\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 48 "Rovnov\341ha v syst\351mu obsahuj\355c\355m t\370i kapaln \351 f\341ze" }}{PARA 0 "" 0 "" {TEXT -1 96 "L\341tky A, B, C tvo\370 \355 p\370i teplot\354 25 \260C za norm\341ln\355ho tlaku t\370i f\341 ze o slo\236en\355 (mol\341rn\355 procenta):" }}{PARA 0 "" 0 "" {TEXT -1 1 " " }}{PARA 0 "" 0 "" {TEXT -1 434 " F\341ze L\341tka A L\341tka B L\341tka C\n I 10 % 10 % 80 %\n II 75 % \+ 10 % 15 %\n III 5 % \+ 90 % 5 %\n\nVznikne sm\355ch\341n\355m 5 mol\371 l \341tky A, 5 mol\371 l\341tky B a 10 mol\371 l\341tky C t\370\355f\341 zov\375 syst\351m? Ur\350ete l\341tkov\341 mno\236stv\355 jednotliv \375ch f\341z\355. \n[nI = 11,346 mol, nII = 4,904 mol, nIII = 3,75 m ol]" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 "Data" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 "xAI:=0.1; xBI:=0.1; xCI:=0.8;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$xAIG$\"\"\"!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$xBIG$\"\" \"!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$xCIG$\"\")!\"\"" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "xAII:=0.75; xBII:=0.1; xCII: =0.15;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%xAIIG$\"#v!\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%xBIIG$\"\"\"!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%xCIIG$\"#:!\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 37 "xAIII:=0.05; xBIII:=0.9; xCIII:=0.05;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&xAIIIG$\"\"&!\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&xBIIIG$\"\"*!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&xCIII G$\"\"&!\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "nA:=5.; nB:= 5.; nC:=10.;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#nAG$\"\"&\"\"!" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#nBG$\"\"&\"\"!" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#nCG$\"#5\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 "\330e\232en\355" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "rA:=nA=nI*xAI+nII*xAII+nIII* xAIII;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#rAG/$\"\"&\"\"!,(*&$\"\" \"!\"\"F,%#nIGF,F,*&$\"#v!\"#F,%$nIIGF,F,*&$F'F2F,%%nIIIGF,F," }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "rB:=nB=nI*xBI+nII*xBII+nIII* xBIII;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#rBG/$\"\"&\"\"!,(*&$\"\" \"!\"\"F,%#nIGF,F,*&F+F,%$nIIGF,F,*&$\"\"*F-F,%%nIIIGF,F," }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "rC:=nC=nI*xCI+nII*xCII+nIII*xCIII; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#rCG/$\"#5\"\"!,(*&$\"\")!\"\"\" \"\"%#nIGF.F.*&$\"#:!\"#F.%$nIIGF.F.*&$\"\"&F3F.%%nIIIGF.F." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "r:=nA+nB+nC=nI+nII+nIII;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"rG/$\"#?\"\"!,(%#nIG\"\"\"%$nIIGF+ %%nIIIGF+" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "solve(\{rA,rB, rC\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<%/%%nIIIG$\"++++]P!\"*/%$nI IG$\"+ah%Q!\\F(/%#nIG$\"+&Q:Y8\"!\")" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}{SECT 1 {PARA 3 "" 0 " " {TEXT -1 63 "Ur\350en\355 rovnov\341hy kapalina-kapalina z dodatkov \351 Gibbsovy energie" }}{PARA 0 "" 0 "" {TEXT -1 93 "Dodatkov\341 Gib bsova energie sm\354si dvou kapaln\375ch l\341tek je p\370i teplot\354 298,15 K pops\341na vztahem" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 257 "" 0 "" {TEXT -1 35 "Ge / (R*T) = x1*x2*(2+1.1*(x2-x1))," }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 247 "kde x1 a x2 js ou mol\341rn\355 zlomky obou slo\236ek. Zjist\354te, zda-li je tento s zst\351m v cel\351m koncentra\350n\355m rozsahu homogenn\355 nebo vytv \341\370\355 rovnov\341hu kapalina-kaplina a p\370\355padn\354 ur\350e te slo\236en\355 koexistuj\355c\355ch f\341z\355. 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Rozd\354lovac\355 konstant a fenolu mezi butylacet\341t(B) a vodu(V) m\341 p\370i teplot\354 30 \+ \260C hodnotu vypl\375vaj\355c\355 z rovnice " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 257 "" 0 "" {TEXT -1 19 "KN = c(B)/c(V) = 55" }} {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 488 "kde c(B) , pop\370. c(V) ud\341v\341 koncentraci fenolu v butylacet\341tov\351, pop\370. vodn\351 f\341zi v g/dm^3. Jestli\236e odpadn\355 voda obsah uje 20 g fenolu na 1 dm^3, vypo\350t\354te:\na) Mno\236stv\355 butylac et\341tu, kter\351 mus\355me pou\236\355t k extrakci, m\341-li se sn \355\236it obsah fenolu na 0,1 % p\371vodn\355 hodnoty jednor\341zovou extrakc\355.\nb) Kolikr\341t je nutno prov\351st extrakci s pou\236it \355m 100 cm^3 butylacet\341tu, chceme-li rovn\354\236 sn\355\236it ob sah fenolu na 0,1 % p\371vodn\355 hodnoty. Vypo\350\355tejte tak\351 k oncentraci fenolu ve vod\354 po ka\236d\351 extrakci." }}{PARA 0 "" 0 "" {TEXT -1 113 "[a) VB = 18,16 dm^3, b) n = 4, c1 = 3,08 g/dm^3, \+ c2 = 0,47 g/dm^3, c3 = 0,073 g/dm^3, c4 = 0,011 g/dm^3]" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 13 "Obecn\351 \370e\232en\355" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "r1:=c0*VV=c1*VV+c1B*VB;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r1G/*&%#c0G\"\"\"%#VVGF(,&*&%#c1GF(F)F(F(*&%$c1BGF(% #VBGF(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "r2:=c1B/c1=KN; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#r2G/*&%$c1BG\"\"\"%#c1G!\"\"%#K NG" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "solve(\{r1,r2\},\{c1, c1B\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<$/%#c1G*(%#c0G\"\"\"%#VVGF (,&F)F(*&%#KNGF(%#VBGF(F(!\"\"/%$c1BG**F,F(F'F(F)F(F*F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "assign(%);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 "Data" } }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "KN:=55.;" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%#KNG$\"#b\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "c0:=20.;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#c0G$\"# ?\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "cx:=c0*0.001;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#cxG$\"#?!\"$" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 6 "VV:=1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#VV G\"\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "DVB:=0.1;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%$DVBG$\"\"\"!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 " \330e\232en\355" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "solve(\{c 1=cx\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<#/%#VBG$\"+OOO;=!\")" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "VB:=DVB;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#VBG$\"\"\"!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "c0;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"#?\"\"!" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "for i from 1 to 5 do " }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "print(i); c1; c0:=c1;" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "od;" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+xI#p2$!\"*" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#c0G$\"+xI#p 2$!\"*" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+6ysLZ!#5" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#c0G$ \"+6ysLZ!#5" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+r\"eEG(!#6" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% #c0G$\"+r\"eEG(!#6" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"%" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+\\*3/7\"!#6" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#c0G$\"+\\*3/7\"!#6" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#\"\"&" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+vgqB%#c0G$\"+vgqB " 0 "" {MPLTEXT 1 0 7 "c0:=20;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#c0G\"#?" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 26 "cn:=c0*(VV/(VV+KN*DVB))^n;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#cnG,$*&\"#?\"\"\")$\"+Q:YQ:!#5%\"nGF(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "fsolve(cn=cx,n);" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#$\"+)>I/p$!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "n:=ceil(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"nG\"\"%" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 10 "Kryoskopie" }}{PARA 0 "" 0 "" {TEXT -1 142 "L\341hev v\355na (o obsahu 10 hmotnostn\355ch \+ procent ethanolu) ponechan\341 ve\350er na balkon\354 praskla. Na jako u hodnotu minim\341ln\354 v noci poklesla teplota?" }}{PARA 0 "" 0 "" {TEXT -1 16 "[t_min<-4,5 \260C] " }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 "Data" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "R:=8.314; Tt:=273.15; DHt:=6 010.;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"RG$\"%9$)!\"$" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#TtG$\"&:t#!\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$DHtG$\"%5g\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "m1:=0.9; m2:=0.1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6# >%#m1G$\"\"*!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#m2G$\"\"\"!\" \"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 21 "M1:=0.018; M2:=0.046; " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#M1G$\"#=!\"$" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%#M2G$\"#Y!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 "\330e\232en \355" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "Kk:=R*Tt^2/DHt*M1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#KkG$\"+9#\\y&=!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "n2:=m2/M2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#n2G$\"+VI\"R<#!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "DT:=-Kk*n2/m1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%# DTG$!+([ev[%!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}} {SECT 1 {PARA 3 "" 0 "" {TEXT -1 12 "Ebulioskopie" }}{PARA 0 "" 0 "" {TEXT -1 157 "P\370\355davek 3,2 g s\355ry do 1000 g sirouhl\355ku (Ke = 2,50 K.kg/mol) m\354l za n\341sledek zv\375\232en\355 bodu varu o D elta T = 0,031 K. Ur\350ete mol\341rn\355 hmotnost rozpu\232t\354n\351 s\355ry." }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}} {SECT 1 {PARA 4 "" 0 "" {TEXT -1 4 "Data" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "m1:=1.; m2:=0.0032;" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#>%#m1G$\"\"\"\"\"!" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#m2G$\"#K!\" %" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "Ke:=2.5;" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#>%#KeG$\"#D!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "DT:=0.031;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DTG$ \"#J!\"$" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 6 "\330e\232en\355" }}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 18 "r:=DT=Ke*m2/M2/m1;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"rG/$\"#J!\"$,$*&$\"+++++!)!#7\"\"\"%#M2G!\"\"F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "solve(r);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+h^k!e#!#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "nS:=%/0.032;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#nSG$\"+Gh^k!) !\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}}}{MARK "8" 0 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 } {PAGENUMBERS 0 1 2 33 1 1 }